Given numbers are 289,698,668

The least common multiple of numbers can be find using the prime factorization method or LCM formula.

The LCM of 289,698,668 is 67375148.

Find LCM of 289,698,668 with Prime Factorization

Multiply the prime numbers at the bottom and the left side.

2 x 289 x 349 x 334 = 67375148

Therefore, the lowest common multiple of 289,698,668 is 67375148.

LCM formula is LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}

Firstly, we have to find the product of all the numbers.

289 x 698 x 668 = 134750296

Then, let us find the GCF of these five numbers. To do so, we have to list down the factors for each number and choose the highest factor that is in all of the lists.

289 : 1, 17, 289

698 : 1, 2, 349, 698

668 : 1, 2, 4, 167, 334, 668

1 is the greatest number that appears in all the lists. Therefore, we can determine that the GCF of 289,698,668, is 1.

Now, the common factors can be found like this.

289:17x 17

698:2x 349

668:2x 2x 167

From this, we can see that the common factors because they appear for more than two numbers. So, just multiply them all together.

2 = 2

Therefore, the value for common factors is 2.

Now that we have all the elements of the formula, we can plug them in to calculate the LCM.

LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}

LCM = 134750296/(1x2)

LCM = 134750296/2

LCM = 67375148

Thus, we can understand that the LCM of 289,698,668 is 67375148.

Here are some samples of LCM of two or more Numbers calculations.

• LCM of 946, 896, 722
• LCM of 228, 567, 395
• LCM of 358, 278, 718
• LCM of 386, 949, 703
• LCM of 728, 168, 679

1. What is the LCM of 289, 698, 668?

Answer: LCM of 289, 698, 668 is 67375148.

2. How to calculate the LCM of 289, 698, 668?

The LCM can be found using two methods. You can either use the LCM formula or the prime factorization method to calculate the LCM of 289, 698, 668.

3. What is the LCM formula?

The LCM formula is LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}.