STRINGS Interview Questions :-
1. Explain What is the difference between a string copy (strcpy) and a memory copy (memcpy)? When should each be used?
The strcpy() function is designed to work exclusively with strings. It copies each byte of the source string to the destination string and stops when the terminating null character (\0) has been moved. On the other hand, the memcpy() function is designed to work with any type of data.
Because not all data ends with a null character, you must provide the memcpy() function with the number of bytes you want to copy from the source to the destination. The following program shows examples of both the strcpy() and the memcpy() functions:
#include
#include
typedef struct cust_str {
int id;
char last_name[20];
char first_name[15];
} CUSTREC;
void main(void);
void main(void)
{
char* src_string = “This is the source string”;
char dest_string[50];
CUSTREC src_cust;
CUSTREC dest_cust;
printf(“Hello! I’m going to copy src_string into dest_string!\n”);
/* Copy src_string into dest_string. Notice that the destination
string is the first argument. Notice also that the strcpy()
function returns a pointer to the destination string. */
printf(“Done! dest_string is: %s\n”,
strcpy(dest_string, src_string));
printf(“Encore! Let’s copy one CUSTREC to another.\n”);
printf(“I’ll copy src_cust into dest_cust.\n”);
/* First, initialize the src_cust data members. */
src_cust.id = 1;
strcpy(src_cust.last_name, “Strahan”);
strcpy(src_cust.first_name, “Troy”);
/* Now, use the memcpy() function to copy the src_cust structure to
the dest_cust structure. Notice that, just as with strcpy(), the
destination comes first. */
memcpy(&dest_cust, &src_cust, sizeof(CUSTREC));
printf(“Done! I just copied customer number #%d (%s %s).”,
dest_cust.id, dest_cust.first_name, dest_cust.last_name);
}
When dealing with strings, you generally should use the strcpy() function, because it is easier to use with strings. When dealing with abstract data other than strings (such as structures), you should use the memcpy() function.
2. Explain How can I remove the trailing spaces from a string?
The C language does not provide a standard function that removes trailing spaces from a string. It is easy, however, to build your own function to do just this. The following program uses a custom function named rtrim() to remove the trailing spaces from a string. It carries out this action by iterating through the string backward, starting at the character before the terminating null character (\0) and ending when it finds the first nonspace character. When the program finds a nonspace character, it sets the next character in the string to the terminating null character (\0), thereby effectively eliminating all the trailing blanks. Here is how this task is performed:
#include
#include
void main(void);
char* rtrim(char*);
void main(void)
{
char* trail_str = “This string has trailing spaces in it. “;
/* Show the status of the string before calling the rtrim()
function. */
printf(“Before calling rtrim(), trail_str is ‘%s’\n”, trail_str);
printf(“and has a length of %d.\n”, strlen(trail_str));
/* Call the rtrim() function to remove the trailing blanks. */
rtrim(trail_str);
/* Show the status of the string
after calling the rtrim() function. */
printf(“After calling rtrim(), trail_str is ‘%s’\n”, trail_str);
printf(“and has a length of %d.\n”, strlen(trail_str));
}
/* The rtrim() function removes trailing spaces from a string. */
char* rtrim(char* str)
{
int n = strlen(str) – 1; /* Start at the character BEFORE
the null character (\0). */
while (n>0) /* Make sure we don’t go out of bounds… */
{
if (*(str+n) != ‘ ‘) /* If we find a nonspace character: */
{
*(str+n+1) = ‘\0’; /* Put the null character at one
character past our current
position. */
break; /* Break out of the loop. */
}
else /* Otherwise, keep moving backward in the string. */
n–;
}
return str; /* Return a pointer to the string. */
}
Notice that the rtrim() function works because in C, strings are terminated by the null character. With the insertion of a null character after the last nonspace character, the string is considered terminated at that point, and all characters beyond the null character are ignored.
3. How can I remove the leading spaces from a string?
The C language does not provide a standard function that removes leading spaces from a string. It is easy, however, to build your own function to do just this. you can easily construct a custom function that uses the rtrim() function in conjunction with the standard C library function strrev() to remove the leading spaces from a string. Look at how this task is performed:
#include
#include
void main(void);
char* ltrim(char*);
char* rtrim(char*);
void main(void)
{
char* lead_str = ” This string has leading spaces in it.”;
/* Show the status of the string before calling the ltrim()
function. */
printf(“Before calling ltrim(), lead_str is ‘%s’\n”, lead_str);
printf(“and has a length of %d.\n”, strlen(lead_str));
/* Call the ltrim() function to remove the leading blanks. */
ltrim(lead_str);
/* Show the status of the string
after calling the ltrim() function. */
printf(“After calling ltrim(), lead_str is ‘%s’\n”, lead_str);
printf(“and has a length of %d.\n”, strlen(lead_str));
}
/* The ltrim() function removes leading spaces from a string. */
char* ltrim(char* str)
{
strrev(str); /* Call strrev() to reverse the string. */
rtrim(str); /* Call rtrim() to remove the “trailing” spaces. */
strrev(str); /* Restore the string’s original order. */
return str; /* Return a pointer to the string. */
}
/* The rtrim() function removes trailing spaces from a string. */
char* rtrim(char* str)
{
int n = strlen(str) – 1; /* Start at the character BEFORE
the null character (\0). */
while (n>0) /* Make sure we don’t go out of bounds… */
{
if (*(str+n) != ‘ ‘) /* If we find a nonspace character: */
{
*(str+n+1) = ‘\0’; /* Put the null character at one
character past our current
position. */
break; /* Break out of the loop. */
}
else /* Otherwise, keep moving backward in the string. */
n–;
}
return str; /* Return a pointer to the string. */
}
Notice that the ltrim() function performs the following tasks: First, it calls the standard C library function strrev(), which reverses the string that is passed to it. This action puts the original string in reverse order, thereby creating “trailing spaces” rather than leading spaces. Now, the rtrim() function is used to remove the “trailing spaces” from the string. After this task is done, the strrev() function is called again to “reverse” the string, thereby putting it back in its original order.
4. Explain How can I right-justify a string?
Even though the C language does not provide a standard function that right-justifies a string, you can easily build your own function to perform this action. Using the rtrim() function, you can create your own function to take a string and right-justify it. Here is how this task is accomplished:
#include
#include
#include
void main(void);
char* rjust(char*);
char* rtrim(char*);
void main(void)
{
char* rjust_str = “This string is not right-justified. “;
/* Show the status of the string before calling the rjust()
function. */
printf(“Before calling rjust(), rjust_str is ‘%s’\n.”, rjust_str);
/* Call the rjust() function to right-justify this string. */
rjust(rjust_str);
/* Show the status of the string
after calling the rjust() function. */
printf(“After calling rjust(), rjust_str is ‘%s’\n.”, rjust_str);
}
/* The rjust() function right-justifies a string. */
char* rjust(char* str)
{
int n = strlen(str); /* Save the original length of the string. */
char* dup_str;
dup_str = strdup(str); /* Make an exact duplicate of the string. */
rtrim(dup_str); /* Trim off the trailing spaces. */
/* Call sprintf() to do a virtual “printf” back into the original
string. By passing sprintf() the length of the original string,
we force the output to be the same size as the original, and by
default the sprintf() right-justifies the output. The sprintf()
function fills the beginning of the string with spaces to make
it the same size as the original string. */
sprintf(str, “%*.*s”, n, n, dup_str);
free(dup_str); /* Free the memory taken by
the duplicated string. */
return str; /* Return a pointer to the string. */
}
/* The rtrim() function removes trailing spaces from a string. */
char* rtrim(char* str)
{
int n = strlen(str) – 1; /* Start at the character BEFORE the null
character (\0). */
while (n>0) /* Make sure we don’t go out of bounds… */
{
if (*(str+n) != ‘ ‘) /* If we find a nonspace character: */
{
*(str+n+1) = ‘\0’; /* Put the null character at one
character past our current
position. */
break; /* Break out of the loop. */
}
else /* Otherwise, keep moving backward in the string. */
n–;
}
return str; /* Return a pointer to the string. */
}
The rjust() function first saves the length of the original string in a variable named n. This step is needed because the output string must be the same length as the input string. Next, the rjust() function calls the standard C library function named strdup() to create a duplicate of the original string. A duplicate of the string is required because the original version of the string is going to be overwritten with a right-justified version. After the duplicate string is created, a call to the rtrim() function is invoked (using the duplicate string, not the original), which eliminates all trailing spaces from the duplicate string.
Next, the standard C library function sprintf() is called to rewrite the new string to its original place in memory. The sprintf() function is passed the original length of the string (stored in n), thereby forcing the output string to be the same length as the original. Because sprintf() by default right-justifies string output, the output string is filled with leading spaces to make it the same size as the original string. This has the effect of right-justifying the input string. Finally, because the strdup() function dynamically allocates memory, the free() function is called to free up the memory taken by the duplicate string.
5. Explain How can I pad a string to a known length?
Padding strings to a fixed length can be handy when you are printing fixed-length data such as tables or spreadsheets. You can easily perform this task using the printf() function. The following example program shows how to accomplish this task:
#include
char *data[25] = {
“REGION”, “–Q1–“, “–Q2–“, “–Q3–“, ” –Q4–“,
“North”, “10090.50”, “12200.10”, “26653.12”, “62634.32”,
“South”, “21662.37”, “95843.23”, “23788.23”, “48279.28”,
“East”, “23889.38”, “23789.05”, “89432.84”, “29874.48”,
“West”, “85933.82”, “74373.23”, “78457.23”, “28799.84” };
void main(void);
void main(void)
{
int x;
for (x=0; x<25; x++)
{
if ((x % 5) == 0 && (x != 0))
printf(“\n”);
printf(“%-10.10s”, data[x]);
}
}
In this example, a character array (char* data[]) is filled with this year’s sales data for four regions. Of course, you would want to print this data in an orderly fashion, not just print one figure after the other with no formatting. This being the case, the following statement is used to print the data:
printf(“%-10.10s”, data[x]);
The “%-10.10s” argument tells the printf() function that you are printing a string and you want to force it to be 10 characters long. By default, the string is right-justified, but by including the minus sign (-) before the first 10, you tell the printf() function to left-justify your string. This action forces the printf() function to pad the string with spaces to make it 10 characters long. The result is a clean, formatted spreadsheet-like
output:
REGION –Q1– –Q2– –Q3– –Q4–
North 10090.50 12200.10 26653.12 62634.32
South 21662.37 95843.23 23788.23 48279.28
East 23889.38 23789.05 89432.84 29874.48
West 85933.82 74373.23 78457.23 28799.84
6. How can I copy just a portion of a string?
You can use the standard C library function strncpy() to copy one portion of a string into another string. The strncpy() function takes three arguments: the first argument is the destination string, the second argument is the source string, and the third argument is an integer representing the number of characters you want to copy from the source string to the destination string. For example, consider the following program, which uses the strncpy() function to copy portions of one string to another:
#include
#include
void main(void);
void main(void)
{
char* source_str = “THIS IS THE SOURCE STRING”;
char dest_str1[40] = {0}, dest_str2[40] = {0};
/* Use strncpy() to copy only the first 11 characters. */
strncpy(dest_str1, source_str, 11);
printf(“How about that! dest_str1 is now: ‘%s’!!!\n”, dest_str1);
/* Now, use strncpy() to copy only the last 13 characters. */
strncpy(dest_str2, source_str + (strlen(source_str) – 13), 13);
printf(“Whoa! dest_str2 is now: ‘%s’!!!\n”, dest_str2);
}
The first call to strncpy() in this example program copies the first 11 characters of the source string into dest_str1. This example is fairly straightforward, one you might use often. The second call is a bit more complicated and deserves some explanation. In the second argument to the strncpy() function call, the total length of the source_str string is calculated (using the strlen() function). Then, 13 (the number of characters you want to print) is subtracted from the total length of source_str. This gives the number of remaining characters in source_str. This number is then added to the address of source_str to give a pointer to an address in the source string that is 13 characters from the end of source_str.
Then, for the last argument, the number 13 is specified to denote that 13 characters are to be copied out of the string. The combination of these three arguments in the second call to strncpy() sets dest_str2 equal to the last 13 characters of source_str.
The example program prints the following output:
How about that! dest_str1 is now: ‘THIS IS THE’!!!
Whoa! dest_str2 is now: ‘SOURCE STRING’!!!
Notice that before source_str was copied to dest_str1 and dest_st2, dest_str1 and dest_str2 had to be initialized to null characters (\0). This is because the strncpy() function does not automatically append a null character to the string you are copying to. Therefore, you must ensure that you have put the null character after the string you have copied, or else you might wind up with garbage being printed.
7. Explain How can I convert a number to a string?
The standard C library provides several functions for converting numbers of all formats (integers, longs, floats, and so on) to strings and vice versa. One of these functions, itoa(), is used here to illustrate how an integer is converted to a string:
#include
#include
void main(void);
void main(void)
{
int num = 100;
char str[25];
itoa(num, str, 10);
printf(“The number ‘num’ is %d and the string ‘str’ is %s.\n”,
num, str);
}
Notice that the itoa() function takes three arguments: the first argument is the number you want to convert to the string, the second is the destination string to put the converted number into, and the third is the base, or radix, to be used when converting the number. The preceding example uses the common base 10 to convert the number to the string.
The following functions can be used to convert integers to strings:
Function Name Purpose
itoa() – Converts an integer value to a string.
ltoa() – Converts a long integer value to a string.
ultoa() – Converts an unsigned long integer value to a string.
Note that the itoa(), ltoa(), and ultoa() functions are not ANSI compatible. An alternative way to convert an integer to a string (that is ANSI compatible) is to use the sprintf() function, as in the following example:
#include
#include
void main(void);
void main(void)
{
int num = 100;
char str[25];
sprintf(str, “%d”, num);
printf(“The number ‘num’ is %d and the string ‘str’ is %s.\n”,
num, str);
}
When floating-point numbers are being converted, a different set of functions must be used. Here is an example of a program that uses the standard C library function fcvt() to convert a floating-point value to a string:
#include
#include
void main(void);
void main(void)
{
double num = 12345.678;
char* str;
int dec_pl, sign, ndigits = 3; /* Keep 3 digits of precision. */
str = fcvt(num, ndigits, &dec_pl, &sign); /* Convert the float
to a string. */
printf(“Original number: %f\n”, num); /* Print the original
floating-point
value. */
printf(“Converted string: %s\n”, str); /* Print the converted
string’s value */
printf(“Decimal place: %d\n”, dec_pl); /* Print the location of
the decimal point. */
printf(“Sign: %d\n”, sign); /* Print the sign.
0 = positive,
1 = negative. */
}
Notice that the fcvt() function is quite different from the itoa() function used previously. The fcvt() function takes four arguments. The first argument is the floating-point value you want to convert. The second argument is the number of digits to be stored to the right of the decimal point. The third argument is a pointer to an integer that is used to return the position of the decimal point in the converted string. The fourth argument is a pointer to an integer that is used to return the sign of the converted number (0 is positive, 1 is negative).
Note that the converted string does not contain the actual decimal point. Instead, the fcvt() returns the position of the decimal point as it would have been if it were in the string. In the preceding example, the dec_pl integer variable contains the number 5 because the decimal point is located after the fifth digit in the resulting string. If you wanted the resulting string to include the decimal point, you could use the gcvt() function (described in the following table).
The following functions can be used to convert floating-point values to strings:
Function Purpose
ecvt() – Converts a double-precision floating-point value to a string without an embedded decimal point.
fcvt() – Same as ecvt(), but forces the precision to a specified number of digits.
gcvt() – Converts a double-precision floating-point value to a string with an embedded decimal point.
8. Explain How can I convert a string to a number?
The standard C library provides several functions for converting strings to numbers of all formats (integers, longs, floats, and so on) and vice versa. One of these functions, atoi(), is used here to illustrate how a string is converted to an integer:
#include
#include
void main(void);
{
int num;
char* str = “100”;
num = atoi(str);
printf(“The string ‘str’ is %s and the number ‘num’ is %d.\n”,
str, num);
}
To use the atoi() function, you simply pass it the string containing the number you want to convert. The return value from the atoi() function is the converted integer value.
The following functions can be used to convert strings to numbers:
Function Name Purpose
atof() – Converts a string to a double-precision floating-point value.
atoi() – Converts a string to an integer.
atol() – Converts a string to a long integer.
strtod() – Converts a string to a double-precision floating-point value and reports any “leftover” numbers that could not be converted.
strtol() – Converts a string to a long integer and reports any “leftover” numbers that could not be converted.
strtoul() – Converts a string to an unsigned long integer and reports any “leftover” numbers that could not be converted.
Sometimes, you might want to trap overflow errors that can occur when converting a string to a number that results in an overflow condition. The following program shows an example of the strtoul() function, which traps this overflow condition:
#include
#include
#include void main(void);
void main(void)
{
char* str = “1234567891011121314151617181920”;
unsigned long num;
char* leftover;
num = strtoul(str, &leftover, 10);
printf(“Original string: %s\n”, str);
printf(“Converted number: %lu\n”, num);
printf(“Leftover characters: %s\n”, leftover);
}
In this example, the string to be converted is much too large to fit into an unsigned long integer variable. The strtoul() function therefore returns ULONG_MAX (4294967295) and sets the char* leftover to point to the character in the string that caused it to overflow. It also sets the global variable errno to ERANGE to notify the caller of the function that an overflow condition has occurred. The strtod() and strtol() functions work exactly the same way as the strtoul() function shown above. Refer to your C compiler documentation for more information regarding the syntax of these functions.
9. Explain How can you tell whether two strings are the same?
The standard C library provides several functions to compare two strings to see whether they are the same. One of these functions, strcmp(), is used here to show how this task is accomplished:
#include
#include
void main(void);
void main(void)
{
char* str_1 = “abc”;
char* str_2 = “abc”;
char* str_3 = “ABC”;
if (strcmp(str_1, str_2) == 0)
printf(“str_1 is equal to str_2.\n”);
else
printf(“str_1 is not equal to str_2.\n”);
if (strcmp(str_1, str_3) == 0)
printf(“str_1 is equal to str_3.\n”);
else
printf(“str_1 is not equal to str_3.\n”);
}
This program produces the following output:
str_1 is equal to str_2.
str_1 is not equal to str_3.
Notice that the strcmp() function is passed two arguments that correspond to the two strings you want to compare. It performs a case-sensitive lexicographic comparison of the two strings and returns one of the following values:
Return Value Meaning
0 – The first string is greater than the second string.
In the preceding example code, strcmp() returns 0 when comparing str_1 (which is “abc”) and str_2 (which is “abc”). However, when comparing str_1 (which is “abc”) with str_3 (which is “ABC”), strcmp() returns a value greater than 0, because the string “ABC” is greater than (in ASCII order) the string “abc”.
Many variations of the strcmp() function perform the same basic function (comparing two strings), but with slight differences. The following table lists some of the functions available that are similar to strcmp():
Function Name Description
strcmp() – Case-sensitive comparison of two strings
strcmpi() – Case-insensitive comparison of two strings
stricmp() – Same as strcmpi()
strncmp() – Case-sensitive comparison of a portion of two strings
strnicmp() – Case-insensitive comparison of a portion of two strings
Looking at the example provided previously, if you were to replace the call to strcmp() with a call to strcmpi() (a case-insensitive version of strcmp()), the two strings “abc” and “ABC” would be reported as being equal.
10. Explain How do you print only part of a string?
The following program shows how to print only part of a string using the printf() function:
#include
#include
void main(void);
void main(void)
{
char* source_str = “THIS IS THE SOURCE STRING”;
/* Use printf() to print the first 11 characters of source_str. */
printf(“First 11 characters: ‘%11.11s’\n”, source_str);
/* Use printf() to print only the
last 13 characters of source_str. */
printf(“Last 13 characters: ‘%13.13s’\n”,
source_str + (strlen(source_str) – 13));
}
This example program produces the following output:
First 11 characters: ‘THIS IS THE’
Last 13 characters: ‘SOURCE STRING’
The first call to printf() uses the argument “%11.11s” to force the printf() function to make the output exactly 11 characters long. Because the source string is longer than 11 characters, it is truncated, and only the first 11 characters are printed. The second call to printf() is a bit more tricky. The total length of the source_str string is calculated (using the strlen() function). Then, 13 (the number of characters you want to print) is subtracted from the total length of source_str.
This gives the number of remaining characters in source_str. This number is then added to the address of source_str to give a pointer to an address in the source string that is 13 characters from the end of source_str. By using the argument “%13.13s”, the program forces the output to be exactly 13 characters long, and thus the last 13 characters of the string are printed.