Given number is 7412
The factor tree of 7412 is as follows:
| 7412 | ||||||||||
| 2 | 3706 | |||||||||
| 2 | 1853 | |||||||||
| 17 | 109 | |||||||||
7412 = 2 x 3706
3706 = 2 x 1853
1853 = 17 x 109
If we write into multiples it would be 7412 x 2
On splitting 3706 further and writing it as multiples of numbers it would be 1853 x 2.
On splitting 1853 further and writing it as multiples of numbers it would be 109 x 17.
Here are examples of Factor tree calculations.
Here we are providing different methods to find the factors of the number 7412. They are splitting numbers and prime factors.
Splitting Numbers
We can divide the number into either of its two factors. In other words, we are looking for the numbers that when multiplied together eqaul 7412. Let’s start with 2 x 2 x 17 x 109 as it results in 7412 on multiplying. We will now find the factors or ancestors of split factors, just like in any family tree.
Prime Factors
Let’s take a look at 7412 now and we can write as 2 x 2 x 17 x 109 and place those factors on the tree. similarly to prime numbers obtained in the first step 2, 2, 17, 109 obtained here are also prime numbers and we will end up these branches.
1. What is factor tree for 7412 ?
Answer: Prime Factors of 7412 are 2 x 2 x 17 x 109.
2. What are the Prime Factors of 7412 ?
Answer: Prime Factors of 7412 are 2 x 2 x 17 x 109.