Given numbers are 111,429,358

The least common multiple of numbers can be find using the prime factorization method or LCM formula.

The LCM of 111,429,358 is 5682534.

Find LCM of 111,429,358 with Prime Factorization

Multiply the prime numbers at the bottom and the left side.

3 x 37 x 143 x 358 = 5682534

Therefore, the lowest common multiple of 111,429,358 is 5682534.

LCM formula is LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}

Firstly, we have to find the product of all the numbers.

111 x 429 x 358 = 17047602

Then, let us find the GCF of these five numbers. To do so, we have to list down the factors for each number and choose the highest factor that is in all of the lists.

111 : 1, 3, 37, 111

429 : 1, 3, 11, 13, 33, 39, 143, 429

358 : 1, 2, 179, 358

1 is the greatest number that appears in all the lists. Therefore, we can determine that the GCF of 111,429,358, is 1.

Now, the common factors can be found like this.

111:3x 37

429:3x 11x 13

358:2x 179

From this, we can see that the common factors because they appear for more than two numbers. So, just multiply them all together.

3 = 3

Therefore, the value for common factors is 3.

Now that we have all the elements of the formula, we can plug them in to calculate the LCM.

LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}

LCM = 17047602/(1x3)

LCM = 17047602/3

LCM = 5682534

Thus, we can understand that the LCM of 111,429,358 is 5682534.

Here are some samples of LCM of two or more Numbers calculations.

• LCM of 551, 953, 898
• LCM of 230, 446, 130
• LCM of 946, 335, 820
• LCM of 280, 146, 653
• LCM of 401, 224, 568

1. What is the LCM of 111, 429, 358?

Answer: LCM of 111, 429, 358 is 5682534.

2. How to calculate the LCM of 111, 429, 358?

The LCM can be found using two methods. You can either use the LCM formula or the prime factorization method to calculate the LCM of 111, 429, 358.

3. What is the LCM formula?

The LCM formula is LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}.