Given numbers are 121,242,767

The least common multiple of numbers can be find using the prime factorization method or LCM formula.

The LCM of 121,242,767 is 185614.

Find LCM of 121,242,767 with Prime Factorization

Multiply the prime numbers at the bottom and the left side.

11 x 11 x 1 x 2 x 767 = 185614

Therefore, the lowest common multiple of 121,242,767 is 185614.

LCM formula is LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}

Firstly, we have to find the product of all the numbers.

121 x 242 x 767 = 22459294

Then, let us find the GCF of these five numbers. To do so, we have to list down the factors for each number and choose the highest factor that is in all of the lists.

121 : 1, 11, 121

242 : 1, 2, 11, 22, 121, 242

767 : 1, 13, 59, 767

1 is the greatest number that appears in all the lists. Therefore, we can determine that the GCF of 121,242,767, is 1.

Now, the common factors can be found like this.

121:11x 11

242:2x 11x 11

767:13x 59

From this, we can see that the common factors because they appear for more than two numbers. So, just multiply them all together.

11x 11 = 121

Therefore, the value for common factors is 121.

Now that we have all the elements of the formula, we can plug them in to calculate the LCM.

LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}

LCM = 22459294/(1x121)

LCM = 22459294/121

LCM = 185614

Thus, we can understand that the LCM of 121,242,767 is 185614.

Here are some samples of LCM of two or more Numbers calculations.

• LCM of 966, 118, 381
• LCM of 100, 901, 475
• LCM of 996, 329, 256
• LCM of 118, 452, 334
• LCM of 788, 203, 851

1. What is the LCM of 121, 242, 767?

Answer: LCM of 121, 242, 767 is 185614.

2. How to calculate the LCM of 121, 242, 767?

The LCM can be found using two methods. You can either use the LCM formula or the prime factorization method to calculate the LCM of 121, 242, 767.

3. What is the LCM formula?

The LCM formula is LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}.