Given numbers are 126,511,443

The least common multiple of numbers can be find using the prime factorization method or LCM formula.

The LCM of 126,511,443 is 4074714.

Find LCM of 126,511,443 with Prime Factorization

Multiply the prime numbers at the bottom and the left side.

7 x 18 x 73 x 443 = 4074714

Therefore, the lowest common multiple of 126,511,443 is 4074714.

LCM formula is LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}

Firstly, we have to find the product of all the numbers.

126 x 511 x 443 = 28522998

Then, let us find the GCF of these five numbers. To do so, we have to list down the factors for each number and choose the highest factor that is in all of the lists.

126 : 1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, 126

511 : 1, 7, 73, 511

443 : 1, 443

1 is the greatest number that appears in all the lists. Therefore, we can determine that the GCF of 126,511,443, is 1.

Now, the common factors can be found like this.

126:2x 3x 3x 7

511:7x 73

443:443

From this, we can see that the common factors because they appear for more than two numbers. So, just multiply them all together.

7 = 7

Therefore, the value for common factors is 7.

Now that we have all the elements of the formula, we can plug them in to calculate the LCM.

LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}

LCM = 28522998/(1x7)

LCM = 28522998/7

LCM = 4074714

Thus, we can understand that the LCM of 126,511,443 is 4074714.

Here are some samples of LCM of two or more Numbers calculations.

• LCM of 532, 465, 768
• LCM of 853, 276, 160
• LCM of 585, 156, 587
• LCM of 273, 211, 387
• LCM of 596, 167, 427

1. What is the LCM of 126, 511, 443?

Answer: LCM of 126, 511, 443 is 4074714.

2. How to calculate the LCM of 126, 511, 443?

The LCM can be found using two methods. You can either use the LCM formula or the prime factorization method to calculate the LCM of 126, 511, 443.

3. What is the LCM formula?

The LCM formula is LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}.