Given numbers are 268,862,497

The least common multiple of numbers can be find using the prime factorization method or LCM formula.

The LCM of 268,862,497 is 57407476.

Find LCM of 268,862,497 with Prime Factorization

Multiply the prime numbers at the bottom and the left side.

2 x 134 x 431 x 497 = 57407476

Therefore, the lowest common multiple of 268,862,497 is 57407476.

LCM formula is LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}

Firstly, we have to find the product of all the numbers.

268 x 862 x 497 = 114814952

Then, let us find the GCF of these five numbers. To do so, we have to list down the factors for each number and choose the highest factor that is in all of the lists.

268 : 1, 2, 4, 67, 134, 268

862 : 1, 2, 431, 862

497 : 1, 7, 71, 497

1 is the greatest number that appears in all the lists. Therefore, we can determine that the GCF of 268,862,497, is 1.

Now, the common factors can be found like this.

268:2x 2x 67

862:2x 431

497:7x 71

From this, we can see that the common factors because they appear for more than two numbers. So, just multiply them all together.

2 = 2

Therefore, the value for common factors is 2.

Now that we have all the elements of the formula, we can plug them in to calculate the LCM.

LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}

LCM = 114814952/(1x2)

LCM = 114814952/2

LCM = 57407476

Thus, we can understand that the LCM of 268,862,497 is 57407476.

Here are some samples of LCM of two or more Numbers calculations.

• LCM of 806, 737, 679
• LCM of 120, 749, 600
• LCM of 343, 203, 926
• LCM of 473, 800, 821
• LCM of 373, 624, 400

1. What is the LCM of 268, 862, 497?

Answer: LCM of 268, 862, 497 is 57407476.

2. How to calculate the LCM of 268, 862, 497?

The LCM can be found using two methods. You can either use the LCM formula or the prime factorization method to calculate the LCM of 268, 862, 497.

3. What is the LCM formula?

The LCM formula is LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}.