Given numbers are 506,121,517

The least common multiple of numbers can be find using the prime factorization method or LCM formula.

The LCM of 506,121,517 is 261602.

Find LCM of 506,121,517 with Prime Factorization

Multiply the prime numbers at the bottom and the left side.

11 x 46 x 11 x 47 = 261602

Therefore, the lowest common multiple of 506,121,517 is 261602.

LCM formula is LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}

Firstly, we have to find the product of all the numbers.

506 x 121 x 517 = 31653842

Then, let us find the GCF of these five numbers. To do so, we have to list down the factors for each number and choose the highest factor that is in all of the lists.

506 : 1, 2, 11, 22, 23, 46, 253, 506

121 : 1, 11, 121

517 : 1, 11, 47, 517

11 is the greatest number that appears in all the lists. Therefore, we can determine that the GCF of 506,121,517, is 11.

Now, the common factors can be found like this.

506:2x 11x 23

121:11x 11

517:11x 47

From this, we can see that the common factors because they appear for more than two numbers. So, just multiply them all together.

11 = 11

Therefore, the value for common factors is 11.

Now that we have all the elements of the formula, we can plug them in to calculate the LCM.

LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}

LCM = 31653842/(11x11)

LCM = 31653842/121

LCM = 261602

Thus, we can understand that the LCM of 506,121,517 is 261602.

Here are some samples of LCM of two or more Numbers calculations.

• LCM of 245, 814, 248
• LCM of 970, 644, 967
• LCM of 634, 594, 770
• LCM of 494, 575, 909
• LCM of 674, 152, 144

1. What is the LCM of 506, 121, 517?

Answer: LCM of 506, 121, 517 is 261602.

2. How to calculate the LCM of 506, 121, 517?

The LCM can be found using two methods. You can either use the LCM formula or the prime factorization method to calculate the LCM of 506, 121, 517.

3. What is the LCM formula?

The LCM formula is LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}.