Given numbers are 523,514,610

The least common multiple of numbers can be find using the prime factorization method or LCM formula.

The LCM of 523,514,610 is 81990710.

Find LCM of 523,514,610 with Prime Factorization

Multiply the prime numbers at the bottom and the left side.

2 x 523 x 257 x 305 = 81990710

Therefore, the lowest common multiple of 523,514,610 is 81990710.

LCM formula is LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}

Firstly, we have to find the product of all the numbers.

523 x 514 x 610 = 163981420

Then, let us find the GCF of these five numbers. To do so, we have to list down the factors for each number and choose the highest factor that is in all of the lists.

523 : 1, 523

514 : 1, 2, 257, 514

610 : 1, 2, 5, 10, 61, 122, 305, 610

1 is the greatest number that appears in all the lists. Therefore, we can determine that the GCF of 523,514,610, is 1.

Now, the common factors can be found like this.

523:523

514:2x 257

610:2x 5x 61

From this, we can see that the common factors because they appear for more than two numbers. So, just multiply them all together.

2 = 2

Therefore, the value for common factors is 2.

Now that we have all the elements of the formula, we can plug them in to calculate the LCM.

LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}

LCM = 163981420/(1x2)

LCM = 163981420/2

LCM = 81990710

Thus, we can understand that the LCM of 523,514,610 is 81990710.

Here are some samples of LCM of two or more Numbers calculations.

• LCM of 373, 929, 371
• LCM of 289, 647, 286
• LCM of 549, 263, 985
• LCM of 529, 406, 103
• LCM of 930, 221, 686

1. What is the LCM of 523, 514, 610?

Answer: LCM of 523, 514, 610 is 81990710.

2. How to calculate the LCM of 523, 514, 610?

The LCM can be found using two methods. You can either use the LCM formula or the prime factorization method to calculate the LCM of 523, 514, 610.

3. What is the LCM formula?

The LCM formula is LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}.