Given numbers are 734,847,121

The least common multiple of numbers can be find using the prime factorization method or LCM formula.

The LCM of 734,847,121 is 621698.

Find LCM of 734,847,121 with Prime Factorization

Multiply the prime numbers at the bottom and the left side.

11 x 11 x 734 x 7 x 1 = 621698

Therefore, the lowest common multiple of 734,847,121 is 621698.

LCM formula is LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}

Firstly, we have to find the product of all the numbers.

734 x 847 x 121 = 75225458

Then, let us find the GCF of these five numbers. To do so, we have to list down the factors for each number and choose the highest factor that is in all of the lists.

734 : 1, 2, 367, 734

847 : 1, 7, 11, 77, 121, 847

121 : 1, 11, 121

1 is the greatest number that appears in all the lists. Therefore, we can determine that the GCF of 734,847,121, is 1.

Now, the common factors can be found like this.

734:2x 367

847:7x 11x 11

121:11x 11

From this, we can see that the common factors because they appear for more than two numbers. So, just multiply them all together.

11x 11 = 121

Therefore, the value for common factors is 121.

Now that we have all the elements of the formula, we can plug them in to calculate the LCM.

LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}

LCM = 75225458/(1x121)

LCM = 75225458/121

LCM = 621698

Thus, we can understand that the LCM of 734,847,121 is 621698.

Here are some samples of LCM of two or more Numbers calculations.

• LCM of 346, 608, 568
• LCM of 825, 432, 576
• LCM of 357, 523, 779
• LCM of 923, 591, 969
• LCM of 861, 909, 495

1. What is the LCM of 734, 847, 121?

Answer: LCM of 734, 847, 121 is 621698.

2. How to calculate the LCM of 734, 847, 121?

The LCM can be found using two methods. You can either use the LCM formula or the prime factorization method to calculate the LCM of 734, 847, 121.

3. What is the LCM formula?

The LCM formula is LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}.