Given numbers are 807,261,838

The least common multiple of numbers can be find using the prime factorization method or LCM formula.

The LCM of 807,261,838 is 58835142.

Find LCM of 807,261,838 with Prime Factorization

Multiply the prime numbers at the bottom and the left side.

3 x 269 x 87 x 838 = 58835142

Therefore, the lowest common multiple of 807,261,838 is 58835142.

LCM formula is LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}

Firstly, we have to find the product of all the numbers.

807 x 261 x 838 = 176505426

Then, let us find the GCF of these five numbers. To do so, we have to list down the factors for each number and choose the highest factor that is in all of the lists.

807 : 1, 3, 269, 807

261 : 1, 3, 9, 29, 87, 261

838 : 1, 2, 419, 838

1 is the greatest number that appears in all the lists. Therefore, we can determine that the GCF of 807,261,838, is 1.

Now, the common factors can be found like this.

807:3x 269

261:3x 3x 29

838:2x 419

From this, we can see that the common factors because they appear for more than two numbers. So, just multiply them all together.

3 = 3

Therefore, the value for common factors is 3.

Now that we have all the elements of the formula, we can plug them in to calculate the LCM.

LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}

LCM = 176505426/(1x3)

LCM = 176505426/3

LCM = 58835142

Thus, we can understand that the LCM of 807,261,838 is 58835142.

Here are some samples of LCM of two or more Numbers calculations.

• LCM of 497, 204, 431
• LCM of 992, 724, 331
• LCM of 808, 438, 129
• LCM of 516, 250, 829
• LCM of 332, 676, 851

1. What is the LCM of 807, 261, 838?

Answer: LCM of 807, 261, 838 is 58835142.

2. How to calculate the LCM of 807, 261, 838?

The LCM can be found using two methods. You can either use the LCM formula or the prime factorization method to calculate the LCM of 807, 261, 838.

3. What is the LCM formula?

The LCM formula is LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}.