Given numbers are 871,323,475

The least common multiple of numbers can be find using the prime factorization method or LCM formula.

The LCM of 871,323,475 is 7033325.

Find LCM of 871,323,475 with Prime Factorization

Multiply the prime numbers at the bottom and the left side.

19 x 871 x 17 x 25 = 7033325

Therefore, the lowest common multiple of 871,323,475 is 7033325.

LCM formula is LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}

Firstly, we have to find the product of all the numbers.

871 x 323 x 475 = 133633175

Then, let us find the GCF of these five numbers. To do so, we have to list down the factors for each number and choose the highest factor that is in all of the lists.

871 : 1, 13, 67, 871

323 : 1, 17, 19, 323

475 : 1, 5, 19, 25, 95, 475

1 is the greatest number that appears in all the lists. Therefore, we can determine that the GCF of 871,323,475, is 1.

Now, the common factors can be found like this.

871:13x 67

323:17x 19

475:5x 5x 19

From this, we can see that the common factors because they appear for more than two numbers. So, just multiply them all together.

19 = 19

Therefore, the value for common factors is 19.

Now that we have all the elements of the formula, we can plug them in to calculate the LCM.

LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}

LCM = 133633175/(1x19)

LCM = 133633175/19

LCM = 7033325

Thus, we can understand that the LCM of 871,323,475 is 7033325.

Here are some samples of LCM of two or more Numbers calculations.

• LCM of 569, 410, 192
• LCM of 665, 240, 738
• LCM of 372, 555, 351
• LCM of 548, 325, 160
• LCM of 218, 892, 163

1. What is the LCM of 871, 323, 475?

Answer: LCM of 871, 323, 475 is 7033325.

2. How to calculate the LCM of 871, 323, 475?

The LCM can be found using two methods. You can either use the LCM formula or the prime factorization method to calculate the LCM of 871, 323, 475.

3. What is the LCM formula?

The LCM formula is LCM(a1, a2, an) = (a1 x a2 x an)/{GCF(a1 x a2 x an) x common factors}.