Online GCD Calculator is useful to find the GCD of 133, 497, 159 quickly. Get the easiest ways to solve the greatest common divisor of 133, 497, 159 i.e 1 in different methods as follows.
Given Input numbers are 133, 497, 159
In the factoring method, we have to find the divisors of all numbers
Divisors of 133 :
The positive integer divisors of 133 that completely divides 133 are.
1, 7, 19, 133
Divisors of 497 :
The positive integer divisors of 497 that completely divides 497 are.
1, 7, 71, 497
Divisors of 159 :
The positive integer divisors of 159 that completely divides 159 are.
1, 3, 53, 159
GCD of numbers is the greatest common divisor
So, the GCD (133, 497, 159) = 1.
Given numbers are 133, 497, 159
The list of prime factors of all numbers are
Prime factors of 133 are 7 x 19
Prime factors of 497 are 7 x 71
Prime factors of 159 are 3 x 53
The above numbers do not have any common prime factor. So GCD is 1
Given numbers are 133, 497, 159
GCD of 2 numbers formula is GCD(a, b) = ( a x b) / LCM(a, b)
Apply this formula for all numbers.
Step1:
LCM(133, 497) = 9443
GCD(133, 497) = ( 133 x 497 ) / 9443
= 133 / 497
= 133
Step2:
LCM(7, 159) = 1113
GCD(7, 159) = ( 7 x 159 ) / 1113
= 7 / 159
= 7
So, Greatest Common Divisor of 133, 497, 159 is 1
Here are some samples of GCD of Numbers calculations.
Given numbers are 133, 497, 159
The greatest common divisor of numbers 133, 497, 159 can be found in various methods such as the LCM formula, factoring, and prime factorization. The GCD of numbers 133, 497, 159 is 1.
1. What is the GCD of 133, 497, 159?
GCD of given numbers 133, 497, 159 is 1
2. How to calculate the greatest common divisor of 133, 497, 159?
We can find the highest common divisor of 133, 497, 159 easily using the prime factorization method. Just list the prime factors of all numbers and pick the highest common factor which is the GCD of 133, 497, 159 i.e 1.
3. How can I use the GCD of 133, 497, 159Calculator?
Out the numbers 133, 497, 159 into the GCD calculator and hit the calculate button to get the greatest common divisor as result.