Are you looking for a way to calculate the greatest common factor of 146, 9240 ? Well, you’re in luck! In this article, we will be showing you how to use two different methods to find the GCF of 146, 9240. We also provide a free GCF of Two or More Numbers Calculator to obtain instant results.
Given numbers are 146, 9240
The greatest common factor of 146, 9240 can be found by using the following 2 different methods.
The GCF of 146, 9240 is 2.
Prime factorization is basically division by prime numbers only. Keep dividing all numbers by the same prime number, until the numbers can no longer be divided by a single prime number. Then, multiply all the prime numbers that are on the left side.
2 | 146, 9240 |
73, 4620 |
∴ Thus, the GCF of given numbers is 2 = 2
The common factor method requires listing down all the factors of 146,9240 that divide each of these numbers without leaving a remainder. To begin, let us list down the factors
list down the factors of 146
1,2,73,146
list down the factors of 9240
1,2,3,4,5,6,7,8,10,11,12,14,15,20,21,22,24,28,30,33,35,40,42,44,55,56,60,66,70,77,84,88,105,110,120,132,140,154,165,168,210,220,231,264,280,308,330,385,420,440,462,616,660,770,840,924,1155,1320,1540,1848,2310,3080,4620,9240
Greatest Common Factor
Once you have listed down the factors, all you have to do is look for the highest factor that appears in all the three aforementioned lists. The greatest number that we can see in all lists is 2 . Therefore, the GCF of 146,9240 is 2
1. What is the GCF of 146, 9240 ?
Answer: GCF of 146, 9240 is 2.
2. How to calculate the GCF of 146, 9240 ?
Answer: You can use two different methods: listing down the factors, and prime factorization. If you want to use the listing method, then simply write down all the factors of 146, 9240. Then, select the greatest number that appears in lists. From this, you will see that the GCF is 2. Next, you can also use the prime factorization method to divide the numbers by prime numbers. Then, multiply the prime numbers on the side to get your answer, which is 2.